Question

The length of a rectangular field is 8 meters less than twice its breadth. If the perimeter of
the rectangular field is 56 meters, find its length and breadth?
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Answer 1

Explanation:

let length be x meters

breadth be y meters

given:

x=2y-8

i.e.

x - 2y = -8 ----> (1)

2x + 2 y = 56 ----> (2)

solving equations (1) and (2)

x = 16 meters

y = 12 meters

therefore,

length = 16 meters

breadth = 12 meters

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Answer 2

Answer:

given that,length of rectangular field is 8metres less than twice to breadth.

perimeter =56 m

Explanation:

let breadth (b)of rectangle be X meter.

then length (l)=(2x-8) m.

a/c to Questions.perimeter of rectangle=56meters

2(L+B)=56

2×(2x-8+X)=56

3x-8=28.

3x=28+8

X=36/3=12meter.

therefore,length(l)=2x-8=2×12-8=16meter.

breadth(b)=X=12meter..

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