Question

what is the possible values of x in the equation x²-4x=45?​

Answer 1

Answer:

I am not sure for answer

Answer 2

The values of x are 9 and -5.

Given:

$x^{2} -4x=45$

To Find:

The possible values of x

Solution:

Given is the quadratic equation.

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c = 0 where a, b, c, ∈ R and a ≠ 0.

Follow are the steps to solve this quadratic equation,

$x^{2} -4x=45\\\\\implies x^{2} -4x-45=0\\\\\implies x^{2} -9x+5x-45=0\\\\\implies x(x-9)+5(x-9)=0\\\\\implies (x-9)(x+5)=0\\\\\implies x = 9,-5$

Therefore, the possible values of x are 9 and -5.

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