Question

the length of a rectangular field is 8 metres less than twice its breadth if the perimeter of the rectangle is 66 metre find its length and breadth​

Answer 1

$\huge\sf\pink{Answer}$

☞ Length = 28 m

☞ Breadth = 5 m

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$\huge\sf\blue{Given}$

✭ Length of a Rectangular land is 8 metres more than Four times it's Width

✭ The perimeter of the land is 66 metres.

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$\huge\sf\gray{To \:Find}$

◈ Its Length and Breadth?

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$\huge\sf\purple{Steps}$

Assume that the length of the rectangular land be L m and breadth be B m

≫ Length is 8 metres more than four times it's width

$\sf{\rightarrowtail L = 4B + 8\qquad -eq(1)}$

Perimeter of a rectangular land is given by,

$\underline{\boxed{\sf Perimeter = 2(Length + Breadth) }}$

$\bullet\underline{\textsf{As Per the Question}}$

$\sf{\dashrightarrow 66 = 2(4B +8+B)}$

$\sf{\dashrightarrow 66 = 2(5B + 8) }$

$\sf{\dashrightarrow \dfrac{66}{2} = 5B + 8 }$

$\sf{\dashrightarrow 33 = 5B + 8}$

$\sf{\dashrightarrow 33- 8 = 5B }$

$\sf{\dashrightarrow 25 = 5B }$

$\sf{\dashrightarrow \dfrac{25}{5} = B}$

$\sf{\orange{\dashrightarrow Breadth = 5 \: m }}$

Substituting the value of B in eq(1)

$\sf{\twoheadrightarrow L = 4 \times 5 + 8 }$

$\sf{\twoheadrightarrow L = 20 + 8 }$

$\sf{\orange{\twoheadrightarrow L = 28 \: m}}$

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