Question

the length of a rectangular field is twice it's breadth if the the perimeter of the field in 288m find the dimensions of the field

Answer 1

Hey!
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▪Let the Breadth of the rectangular Field be - x m


▪Then it's Length will be twice i,e - 2x m


▪Perimeter of Rectangle = 2 × ( L + B )


▪Perimeter Given : 288 m


↪Putting in the formula -


=> 2 × ( x + 2x ) = 288

=> 3x = 144


=> x = 144/3


▪x = 48


✔Breadth x => 48 m

✔Length 2× 48 = 96 m


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Answer 2

• Given: Perimeter of rectangle is 288 m. & Length of rectangle is twice of breadth.

• ❍ Lets consider Breadth of rectangle be x m. Then, Breadth of rectangle will be 2x m.

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We know that,

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$\begin{gathered}\bigstar\:{\underline{\boxed{\sf{\purple{Perimeter_{\:(rectangle)} = 2(Length + Breadth)}}}}}\\\\\\ :\implies\sf 2(2x + x) = 288\\\\\\ :\implies\sf 2 \times 3x = 288\\\\\\:\implies\sf 6x = 288\\\\\\ :\implies\sf x = {\cancel{ \dfrac{288}{6}}}\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{\pink{x = 48}}}}}}\:\bigstar\\\\\end{gathered}$

Hence,

⠀⠀▪︎⠀ Breadth of rectangle, x = 48 m

⠀⠀▪︎⠀ Length of rectangle, 2x = 96 m

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$\therefore\:{\underline{\sf{Length\:\&\:breadth\:of\:rectangle\:is\:{\pmb{96\:m}}\:\&\:{\pmb{48\:m}}\:respectively.}}}$