the length of a rectangular hall exceeds its breadth by 7 m. If the breadth is decreased by 1 m and the length increased by 2 m, the area remains the same. find the length and breadth of the hall.
Answers
Answered by
48
Let breadth =x
therefore length= x+7.
threfore area=x(x+7)........i
also given....
if breadth decreases by 1, length increases by 2 , area
remains unaffected.
therefore area = (x-1)(x+7+2)=(x-1)(x+9).........ii
therefore, i=ii
x^2+7x=x^2+8x-9..
=>x^2-x^2+9=8x-7x
=>9=x
so breadth =x=9
length=x+7=16.
therefore length= x+7.
threfore area=x(x+7)........i
also given....
if breadth decreases by 1, length increases by 2 , area
remains unaffected.
therefore area = (x-1)(x+7+2)=(x-1)(x+9).........ii
therefore, i=ii
x^2+7x=x^2+8x-9..
=>x^2-x^2+9=8x-7x
=>9=x
so breadth =x=9
length=x+7=16.
neha133:
an induction stove marked $3750 is available for $3200 after discount. Find the rate of discount
discount =$ 550
therefore discount percent = discount/original price *100
550/3750*100
14.666667%
thanx
You are great in maths
thanks
Practice lots of maths and someday you too can solve these problems like pro
Ravi bought a new car for $475000.Accessories insurance and tax cost him $20000 after 5 years, He sold the car for $250000 find his loss percent
Answered by
31
Answer:
Step-by-step explanation:
Let the length be :x+7
Let the breadth be:x
After addition and subtraction
Length:x+7+2=x+9
Breadth:x-1
A.T.Q
x(x+7) = (x+9)(x-1)
x²+7x = x(x-1)+9(x-1)
x²+7x = x²-x+9x-9
x²+7x-x²+8x = 9
8x-7x = 9
So, Breadth : 9m
So, Length :16m
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