Question

The length of a rectangular hall is 5 metre more than its breadth and the area of the hall is 594 m square find its perimeter

Answer 1

here's the solution to your question

Answer 2

$\underline{ \bf{QUESTION}} : \\ \\ \tiny \bf{The \: length \: of \: a \: rectangular \: hall \: is \: 5 \: metre \: more \: than \: its } \\ \tiny \bf{ breadth \: and \: the \: area \: of \: the \: hall \: is \: 594m^{2} \: find \: its \: perimeter.} \\ \\ \underline{ \bf{GIVEN}} : \\ \\ \tiny \bf{L = x + 5, \: b = x \: and \: the \: area \: of \: hall \: is \: given \rightarrow \: 594 {m}^{2} } \\ \\ \underline{\bf{FIND}} : \\ \\ \rightarrow\tiny \bf{the \: perimeter \: of \: the \: rectangular \: hall} \\ \\ \underline{\bf{SOLUTION}} : \\ \ = \ 594 = x + 5 \times x \\ \\ = 594 = {x}^{2} + 5x \\ \\ = {x}^{2} + 5x - 594 = 0 \\ \\ = {x}^{2} + (27 - 22)x - 594 = 0 \\ \\ = {x}^{2} + 27x - 22 x - 594 = 0 \\ \\ = x( x + 27) - 22(x + 27) = 0 \\ \\ = (x - 22)( x + 27) = 0 \\ \\ x = 22, \: x = - 27 \\ \\l = x + 5 = 22 + 5 = 27, \: b = 22 \\ \\ \bf{the \: perimeter \: of \: the \: hall \: is \: 2(l + b)} \\ \\ 2(27 + 22) = 2(49) = 98meters$