The length of a rectangular park exceeds its breadth by 17metres lf the perimeter of the park is178metres ,find the dimensions of the park.
Answers
Answered by
2
Let the length of rectangle be x
breadth=x-17
we know that
perimeter of rectangle = 2 (lenght +breadth )
178=2 (x+x-17)
89=2x-17
2x=106
x=53m
lenght =53m
breadth =53-17=36m
breadth=x-17
we know that
perimeter of rectangle = 2 (lenght +breadth )
178=2 (x+x-17)
89=2x-17
2x=106
x=53m
lenght =53m
breadth =53-17=36m
Answered by
2
Let breadth be x
Then length =17+x
We know,
Perimeter=2(l+b)
178=2(17+x+x)
178/2=17+2x
89=17+2x
89-17=2x
72=2x
X=72/2
X=36
breadth=x=36
and
Length=17+x=17+36=53 answer
Then length =17+x
We know,
Perimeter=2(l+b)
178=2(17+x+x)
178/2=17+2x
89=17+2x
89-17=2x
72=2x
X=72/2
X=36
breadth=x=36
and
Length=17+x=17+36=53 answer
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