Math, asked by sharma2006, 11 months ago

the length of a rectangular park is 80m and its breadth is 60m . find the length of the diagonal​

Answers

Answered by manasvi1604
46

Answer:

Step-by-step explanation:

Length of the rectangle = 80 m

Breadth of the rectangle =60 m

A diagonal divides a rectangle into two right angled triangles.

Hence each triangle will have:

  • length as height
  • breadth as base
  • diagonal as hypotenuse

Therefore,

(diagonal)^2 = (length)^2 +(breadth)^2

(diagonal)^2 = 80*80 +60*60

(diagonal)^2 = 6400+3600

(diagonal)^2 = 10000

diagonal= 100 m

HOPE IT HELPS....


lucifer4087: hi
Answered by Sauron
65

\mathfrak{\large{\underline{\underline{Answer :-}}}}

The Diagonal of the Rectangle is 100 m.

\mathfrak{\large{\underline{\underline{Explanation :-}}}}

Given :

Length of the Rectangle = 80m

Breadth of the Rectangle = 60m

To find :

The Diagonal of the Rectangle

Solution :

By using Pythagoras Theorum ;

In ∆ ADC :

• Base = 80 cm (CD)

• Height = 60 cm (AC)

• Hypotenuse = x (AD)

\boxed{\sf{Hypotenuse^{2} = Base^{2}+ Height^{2}}}

\sf{\implies} \:  {x}^{2} =  {80}^{2}  +  {60}^{2}

\sf{\implies} \:  {x}^{2}  = 6400 + 3600

\sf{\implies} \:  {x}^{2}  = 10000

\sf{\implies} \: x =  \sqrt{10000}

\begin{array}{r|l} 2 & 10000 \\\cline{1-2} 2 & 5000 \\\cline{1-2} 2 & 2500 \\ \cline{1-2} 2 & 1250 \\\cline{1-2}  5 & 625 \\\cline{1-2} 5 & 125 \\\cline{1-2} 5 & 25 \\\cline{1-2} 5 & 5 \\\cline{1-2}  & 1\end{array}

\Rightarrow 10000 = 2 × 2 × 2 × 2 × 5 × 5 × 5 × 5

\Rightarrow 2 × 2 × 5 × 5

\Rightarrow 100

\sf{\implies} \: x = 100

The Hypotenuse = 100 m

\therefore The Diagonal of the Rectangle is 100 m.

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