Question

the length of a rectangular park is 80m and its breadth is 60m . find the length of the diagonal​

Answer 1

Answer:

Step-by-step explanation:

Length of the rectangle = 80 m

Breadth of the rectangle =60 m

A diagonal divides a rectangle into two right angled triangles.

Hence each triangle will have:

• length as height
• breadth as base
• diagonal as hypotenuse

Therefore,

(diagonal)^2 = (length)^2 +(breadth)^2

(diagonal)^2 = 80*80 +60*60

(diagonal)^2 = 6400+3600

(diagonal)^2 = 10000

diagonal= 100 m

HOPE IT HELPS....

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Diagonal of the Rectangle is 100 m.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Length of the Rectangle = 80m

Breadth of the Rectangle = 60m

To find :

The Diagonal of the Rectangle

Solution :

By using Pythagoras Theorum ;

In ∆ ADC :

• Base = 80 cm (CD)

• Height = 60 cm (AC)

• Hypotenuse = x (AD)

★ $\boxed{\sf{Hypotenuse^{2} = Base^{2}+ Height^{2}}}$

$\sf{\implies} \: {x}^{2} = {80}^{2} + {60}^{2}$

$\sf{\implies} \: {x}^{2} = 6400 + 3600$

$\sf{\implies} \: {x}^{2} = 10000$

$\sf{\implies} \: x = \sqrt{10000}$

$\begin{array}{r|l} 2 & 10000 \\\cline{1-2} 2 & 5000 \\\cline{1-2} 2 & 2500 \\ \cline{1-2} 2 & 1250 \\\cline{1-2} 5 & 625 \\\cline{1-2} 5 & 125 \\\cline{1-2} 5 & 25 \\\cline{1-2} 5 & 5 \\\cline{1-2} & 1\end{array}$

$\Rightarrow$ 10000 = 2 × 2 × 2 × 2 × 5 × 5 × 5 × 5

$\Rightarrow$ 2 × 2 × 5 × 5

$\Rightarrow$ 100

$\sf{\implies} \: x = 100$

The Hypotenuse = 100 m

$\therefore$ The Diagonal of the Rectangle is 100 m.