The length of a rectangular plate is measured by a metre scale and is found to be 10.0 cm its width is measured by vernier calipers as 1.00 cm the least count of the metre scale and the 100 calliper are 0.1 cm and 0.01 cm respectively find the maximum permissible error in area measured is
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Permissible error in length = 0.1/2 = 0.05
Permissible error in width = 0.005
permissible error in area = The sum of the permissible error in length and with
= 0.05 + 0.005
= 0.055
The permissible error in area = +/- 0.055
Permissible error in width = 0.005
permissible error in area = The sum of the permissible error in length and with
= 0.05 + 0.005
= 0.055
The permissible error in area = +/- 0.055
ParvGoel:
Ur ans is wrong
U are a noob
wrong ans bro
dont write wro g
why the relative error in length is divided by 2
Answered by
1
Answer:
Step-by-step explanation:
Permissible error in length = 0.1/2 = 0.05
Permissible error in width = 0.005
permissible error in area = The sum of the permissible error in length and with
= 0.05 + 0.005
= 0.055
The permissible error in area = +/- 0.055
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