Question

The length of the hypotenuse of a right triangle is one unit more than twice the length of the short side and the other side is one unit less than twice the length of the shortest side . find the length of the other 2 side

Answer 1

HEYA !!...

HERE IS YOUR ANSWER :)

__________________________

Let ABC be the right angled ∆ in which ∠B = 90°.

Let BC = base = shortest side = x cm

Now, AC = hypotenuse = (2x + 1) cm

Now, AB = perpendicular = (2x − 1) cm

Now, AC^2 = AB^2 + BC^2   [Pythagoras theorem]


$= > ( {2x + 1)}^{2} = ( {2x - 1)}^{2} + {x}^{2} \\ \\ = > 4 {x}^{2} + 1 + 4x = 4 {x}^{2} + 1 - 4x + {x}^{2} \\ \\ = > 4x = - 4 x + {x}^{2} \\ \\ = > {x}^{2} - 8x = 0 \\ \\ = > x(x - 8) = 0 \\ \\ = > x = 8 \: \: \: \: or \: \: \: x = 0 \: \: (rejected)$

So, BC = 8 cm

AC = 2×8+1 = 17 cm

AB = 2×8-1 = 15 cm

____________________

HOPE IT HELPS U ☺☺

THANKS !!

# NIKKY

✌ ✌

Answer 2

Answer:

8CM,15CM,17CM

Step-by-step explanation: