The length of rectangle is 5cm more than its breadth and the perimeter exceeds the length by 17cm.then determine the length and breadth of given rectangle
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heya,
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Let the breadth of rec. be x cm
So, the length of rec. be 5+x cm
Perimeter of rec. be 5+x+17 cm
A.T.Q.
2(5+x+x) = 5+x+17
=> 10+2x+2x = 22+x
=> 4x-x = 22-10
=> 3x = 12
=> x = 12/3
=> x = 4
Therefore,
⚫ Breadth of rec.
= x cm
= 4 cm
⚫ Length of rec.
= 5+x cm
= 5+4 cm
= 9 cm
Perimeter of rec.
= 5+x+17 cm
= 5+4+17 cm
= 26 cm
As,
Perimter if rec.
= 2×(9+4) cm
= 2×13 cm
= 26 cm
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______________________________
Let the breadth of rec. be x cm
So, the length of rec. be 5+x cm
Perimeter of rec. be 5+x+17 cm
A.T.Q.
2(5+x+x) = 5+x+17
=> 10+2x+2x = 22+x
=> 4x-x = 22-10
=> 3x = 12
=> x = 12/3
=> x = 4
Therefore,
⚫ Breadth of rec.
= x cm
= 4 cm
⚫ Length of rec.
= 5+x cm
= 5+4 cm
= 9 cm
Perimeter of rec.
= 5+x+17 cm
= 5+4+17 cm
= 26 cm
As,
Perimter if rec.
= 2×(9+4) cm
= 2×13 cm
= 26 cm
_______________________________
I hope this answer helps you.....
You can thank me by marking my answer as BRAINLIEST.....
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