Question

The length of a rectangular room is twice it's breadth If the perimeter of the same room is 180. Find the sides of the room

Answer 1

Answer:

Breadth = x

Length = 2x

Perimeter = 2 ( length + breadth)

180 = 2 ( 2x + x)

180 = 2 ( 3x)

180 = 6x

180/6 = x

30 = x

Breadth = 30

Length = 2x = 2×30 = 60

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Answer 2

★ ${\underline{\underline{\large{\bold{Given:-}}}}}$

• The length of a rectangle room is twice it's Breadth .
• Perimeter of the rectangular room is 180 .

★${\underline{\underline{\large{\bold{To\:find:-}}}}}$

• The sides of the room.

★ ${\underline{\underline{\large{\bold{Solution:-}}}}}$

Consider,

• Length of the rectangular room = x m
• Breadth of the rectangular room = y m.

According to the 1st condition :-

• The length of a rectangle room is twice it's Breadth .

$\to\sf{x=2y..............(1)}$

According to the 2nd condition :-

• Perimeter of the rectangular room is 180.

$\to\sf{2(x+y)=180}$

$\to\sf{2(2y+y)=180\:[put\:x=2y\: from\:eq(1)]}$

$\to\sf{2\times\:3y=180}$

$\to\sf{6y=180}$

$\to\sf{y=30}$

• Breadth = 30 m

Now , put y = 30 in eq 1 for getting the value of x.

$\to\sf{x=2y}$

$\to\sf{x=2\times\:30}$

$\to\sf{x=60}$

• Length = 60 m

Therefore , the sides of the rectangular room are 60 m & 30 m.