Question

the length of a rectangular shaped Park exceeds its breadth by 17 years if the perimeter of the Rs 178 then the diameter of the particle​

Answer 1

Answer:

Park:

length=breadth +17m. (b+17) m

perimeter=2(b+b+17)

= 2x (2b+17)

= 4b +34 =178

4b=178-34

4b =144

b = 144/4=36m

l = 36+17=53m

diagonal=v53^2+36^2 = 4105

= 64.07 m

Answer 2

Answer:

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Let the breadth of the park be = x meters

Then the length of the park = x+17 meters

Perimeter of the park = 2 (length + breadth)

= 2 (x + 17 + x) meters

= 2 (2x + 17) meters

But it is given that the perimeter of the rectangle is 178 meters.

$2(2x + 17) = 178 \\ 4x + 34 = 178 \\ 4x = 178 - 34 \\ 4x = 144 \\ x = \frac{144}{4} = 36$

Therefore breadth of the park = 36 meters

Length of the park = 36+17 = 53 meters.