Question

the length of a rectangular sheet of paper is 3/5 CM and the breadth is 2/5 CM .what is the perimeter of the paper
​

Answer 1

Given :

• Length of the Rectangular sheet of paper = 3/5 CM

• Breadth of the rectangular sheet of paper = 2/5 CM

To Find :

• Perimeter of the paper

Solution :

The perimeter of a rectangle(P) is given by;

$\\ \large\star{\boxed{\purple{\rm{\: P = \: 2(L+ B)}}}}$

We have ,

• Length(L) = 3/5 CM

• Breadth (B) = 2/5 CM

Now , By substituting the values ,

$\\ :\implies \sf \: P = 2 \bigg( \frac{3}{5} + \frac{2}{5}\bigg) \: cm$

$\\ :\implies \sf \: P = 2 \bigg( \frac{3 + 2}{5}\bigg) \: cm$

$\\ :\implies \sf \: P = 2 \bigg( \frac{5}{5} \bigg) \: cm$

$\\ : \implies \sf \: P= 2(1) \: cm$

$\\ : \implies \sf \underline{\boxed{\bf{p = 2 \: cm}}}$

Hence , The Perimeter of the given rectangular sheet of paper is 2 cm.

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

The length of a rectangular sheet of paper is 3/5 CM and the breadth is 2/5 CM .what is the perimeter of the paper

$\huge{\boxed{\rm{\red{Answer}}}}$

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• Length of rectangular sheet of paper = 3/5 cm
• Breath of rectangular sheet of paper = 2/5 cm

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• Perimeter of Rectangular paper.

${\bigstar}\large{\boxed{\sf{\pink{Solution}}}}$

★$\large\green{\texttt{Perimeter of Rectangle}}$

★$\large\green{\texttt{2 (length + breadth )}}$

★$\large\orange{\texttt{2 ( 3/5 + 2/5 )}}$

★$\large\orange{\texttt{2(5/5)}}$

★$\large\orange{\texttt{10/5}}$

★$\large\orange{\texttt{2 cm}}$

MORE TO KNOW -

What is length & breadth ?

The length and breadth of definition is - through all parts of (a place)

What is rectangle ?

It can also be defined as an equiangular quadrilateral, since equiangular means that all of its angles are equal (360°/4 = 90°).

What is Perimeter ?

The word perimeter means a path that surrounds an area. It comes from the Greek word 'peri,' meaning around, and 'metron,' which means measure.

@Itzbeautyqueen23

Hope it's helpful

Thank you :)