Question

The length of a road roller is 2.1m and its diameter is 1.4m. For levelling a ground 500 rotations of the road roller were required. How much area of ground was levelled by the road roller? Find the cost of levelling at the rate of Rs. 7 per sq. m.

Answer 1

Please reply if my answer is correct or incorrect

Answer 2

Answer:

$4615.8\ m^2$, Rs. 32310.6.

Step-by-step explanation:

Given,

length of roller =2.1 m

diameter of roller = 1.4 m

radius of roller =$\dfrac{diameter}{2}$

                        $=\dfrac{1.4}{2}$

                          = 0.7 m

Curved surface area of the roller = 2.π.r.h

                                                       = 2 x 3.14 x 0.7 x 2.1

                                                        $=\ 9.2316\ m^2$

Since, roller makes 500 rotations for the levelling of road. So, the total area of road = 500 x 9.2316

           $= 4615.8\ m^2$

rate of levelling of road = Rs. 7 per meter square

So, the total cost of the levelling of road = 7 x 4615.8 Rs.

                                                                    = Rs. 32310.6

So, the total cost of levelling of road will be Rs. 32310.6.