Question

the length of a road roller is 2m and the diameter of its edge is 50cm . It takes 700 revolutions to level ground . Find the area of the field​

Answer 1

Answer:

$csa = 2\pi \times r \times l$

$area \: of \: field = 700 \times csa$

r=25cm

l=2m=200cm

area of field=700×2π×25×200

area=2200sq.metres

Answer 2

The area of the field is 2200 m².

Given data :

Length of the road roller = 2m = 200cm

Diameter = 50 cm

Revolution = 700

So,

Radius of the road roller = 50/2 = 25 cm

Curved surface area = 2×π×25×200 = 10000 π cm²

Field area = (CSA of road roller × Numbers of revolution) = (10000π × 700) = (10000×22/7×700) = 22000000 cm² = 2200 m² (answer)