Question

The length of a room is 50 per cent more than its breadth.
The cost of carpeting the room at the rate of 38.50m' is
924 and the cost of painting the walls at the rate of $5.50
per m’is* 1,320. Find the dimensions of the room.​

Answer 1

Answer:

length = 50% of breadth + breadth

           = b + b/2

           = 3b / 2

b = b

area = l×b

        = 3b / 2 × b

        = 3b² / 2

given ,

total cost for carpeting the floor = 924 at 38 . 5 for 1 m²

area = 924 / 38 . 5

        = 24 m²

3b² / 2 = 24

3b² = 48

b² = 16

b = √16

  = 4 m

l = 3b / 2

 = 3×4 / 2

 = 6 m

cost of painting 1 wall is 1320 at 5.5 per m²

area of each wall = 1320 / 5.5

                             = 240 m²

The dimensions of the wall are breadth × height .

b×h = 240

4 × h = 240

h = 240 / 4

  = 60 m

Therefore ,

l = 6 m

b = 4 m

h = 60 m

hope it helped and please mark as brainliest:)

Answer 2

Heya ☺

Let the breadth of the room be (x)m. Then,

length = x + 50 % of x

= x + 50/100 × x

= x + x/2

= 2x + x/2

= 3x/2

Area of floor = 924/38.50

=> l × b = 924 × 100/3,850

=> x × 3x/2 = 24

=> 3x^2/2 = 24

=> x^2 = 24 × 2/3

=> x^2 = 16

=> x = √16

=> x = 4

Hence , breadth = 4m

length = 3 × 4/2

= 6m

Area of four walls = 1,320/5.50

=> 2(l+b) × h = 1,320 × 100/55)

=> 2(6+4) × h = 240

=> 10h = 240/2

=> 10h = 120

=> h = 120/10

=> h = 12m

Hence , the dimensions of the room is 6m , 4m and 12m.