Question

The length of a second's hand in watch is Icm.
The change in velocity of its tip in 15 seconds is
(a) zero
Tecmis
302
(C) 30 cm's
(1) The emis​

Answer 1

Answer:

Change in velocity =

√2/15 m/s

Step by step explanations :

given that,

The length of a second's hand in watch is Icm.

so,

taking the second's hand as a radius

whose length = 1 cm

given time interval = 15 seconds,

so,

after 15 seconds,

the second hand will make a right angle,

here,

distance travelled by the minute hand =

arc made by the minute hand,

and,

the displacement of the minute hand =

shortest distance between the two points of the arc

to find,

change in velocity of the minute hand,

displacement of the minute hand/time interval

here,

displacement = √(1¹ + 1²)

= √2 m

and

given time interval = 15 seconds

Change in velocity

= displacement/time interval

= √2/15

so,

Change in velocity =

√2/15 m/s

Answer 2

Answer:

Change in velocity = √2/15 m/s

Step by step explanations :

given that,

The length of a second's hand = 1 cm

time interval = 15 seconds,

after 15 seconds,

the second hand will make a right angle,

now,

change in velocity = displacement/time

= (√1² + 1²)/15

= √2/15 m/s

so,

Change in velocity = √2/15 m/s