The length of a square is increased by a 5th so that its new area is 44cm2 more than the original value. Find the difference in perimeter of two shapes
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perimeter1=4side
44=4s
s=11cm
11-5=6
p2=4*6
p2=24
difference=p1-p2
=44-24
=20
44=4s
s=11cm
11-5=6
p2=4*6
p2=24
difference=p1-p2
=44-24
=20
nityakhanna:
wrong answer
what is right answer
I am sure that my answer is right
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