Question

the length of a string between a kite and a point on the ground is 90m. If the string makes an angle B with the ground level such that tanB = 15/8. How high is the kite (assume that there is no slack in the string).

Answer 1

Find the angle:

$\tan(B) =\dfrac{15}{8}$

$\angle B = \tan^{-1} \bigg (\dfrac{15}{8} \bigg)$

$\angle B = 62 \textdegree$

Find the height:

$\sin (\theta) =\dfrac{\text {opposite}}{\text{hypotenuse}}$

$\sin (62) =\dfrac{\text {height}}{\text{90}}$

$height = 90 \times \sin (62)$

$height = 79 \text { cm}$

Answer: The kite is flying 79 cm above ground.

Answer 2

Here is the answer .........