Question

The length of a table is twice its breadth. The perimeter of the table is 60 m. What are the measures of its dimensions?​

Answer 1

Answer:

Step-by-step explanation:

I = 2b

perimeter=2 (I + b)

= 2(2b+b) = 6b

6b = 60

b = 6o/6=10

I=2b=20

Length=20m

breadth=IOm

Answer 2

To find : dimensions of table .i.e. measures of length and breadth.

Given : length of table is twice its breadth.

            perimeter of table = $60 \ m$

Solution :

• According to given data we write  given condition as :
• $l = 2b$
• Also , we are given that perimeter of table = $60 \ m$  
• Then , perimeter of table =  $2 ( l+ b)$  

• substituting  values we get ,

                                            $60 = 2 ( 2b + b )\\60 = 2\times 3b\\60 = 6b \\b = 10$

• Now , breadth = $10 \ m$
• length = $2b$ = $2\times 10 = 20 \ m$

Hence , measures of length and breadth is  $20 \ m$ and  $10\ m$ respectively.