Question

. The length of a tightly wound coil of wire of uniform thickness was found to be 6.0 cm. Calculate the diameter of the wire if the coil contains 50 turns.​

Answer 1

Answer:

$Number of turns in the coil N=100</p><p>Radius of coil r=0.1 m</p><p>Current flowing in the coil I=1 A</p><p>Magnetic field at the center of the coil B=2rμoIN</p><p>∴ B=2×0.14π×10−7×1×100 \: </p><p>⟹ B=6.28×10−4 T</p><p></p><p>$

Number of turns in the coil N=100

Radius of coil r=0.1 m

Current flowing in the coil I=1 A

Magnetic field at the center of the coil B=2rμoIN

∴ B=2×0.14π×10−7×1×100

⟹ B=6.28×10−4 T