the length of an altitude equilateral triangle is √3 cm find the length of side and perimeter of a triangle
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Hey there!
Given,
Altitude = √3 cm
Let the ΔABC be equilateral triangle.
All angles will be 60°.
And Altitude (AD) will bisect the base.
So, ∠ADC = 90°.
Let the side be a. Then, by pythagoras theorem in ΔADC,
Altitude² + (a/2)² = a²
3² = a²- a²/4
3 = 3a²/4
a² = 4
a = 2 cm
Now,
Perimeter = 3 * side
= 3 * 2 cm
= 6 cm
Hope It Helps You!
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