Question

The length of an aluminium bar is 80cm increase by 1mmon heating . What is the final temperature of the bar if it was initially at temperature 20degree celcius ?

Answer 1

ΔT=T-20

l=800mm

Δl=1mm

α=25x10⁻⁶°C

Δl/l=αΔT

1/800=25*10⁻⁶(T-20)

T-20=10⁶/2x10⁴

T-20=0.5x10²

T-20=50

T=70°C

Answer 2

Answer:

ΔT=T-20

l=800mm

Δl=1mm

α=25x10⁻⁶°C

Δl/l=αΔT

1/800=25*10⁻⁶(T-20)

T-20=10⁶/2x10⁴

T-20=0.5x10²

T-20=50

T=70°C