The length of an aluminium bar is 80cm increase by 1mmon heating . What is the final temperature of the bar if it was initially at temperature 20degree celcius ?
Answers
Answered by
0
ΔT=T-20
l=800mm
Δl=1mm
α=25x10⁻⁶°C
Δl/l=αΔT
1/800=25*10⁻⁶(T-20)
T-20=10⁶/2x10⁴
T-20=0.5x10²
T-20=50
T=70°C
l=800mm
Δl=1mm
α=25x10⁻⁶°C
Δl/l=αΔT
1/800=25*10⁻⁶(T-20)
T-20=10⁶/2x10⁴
T-20=0.5x10²
T-20=50
T=70°C
Answered by
13
Answer:
ΔT=T-20
l=800mm
Δl=1mm
α=25x10⁻⁶°C
Δl/l=αΔT
1/800=25*10⁻⁶(T-20)
T-20=10⁶/2x10⁴
T-20=0.5x10²
T-20=50
T=70°C
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