Question

The length of an edge of a cube increases by 3% when it
is heated through 50c Then the volume
increases
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Answer 1

Answer:

the

Explanation:

the length of an edge of a cube is increased by 3 percentage is and service 300 percentage

Answer 2

Answer:

The volume increases by 9.2727%.

Explanation:

Let the length of the cube be "l".

The volume of the cube is given as(V)=l³     (1)

From the question, we can see that there is an increment of 3% in length when the cube is heated to 50°C. The new length will be,

$l'=(1+0.03)l=1.03l$       (2)

The new volume is given as,

$V'=l'^3$         (3)

By inserting equation (2) in equation (3) we get;

$V'=(1.03l)^3$

$V'=1.092727\ l^3$     (4)

Then the increase in volume is given as,

$\frac{V'-V}{V} \times 100$     (5)

Inserting equations (1) and (4) in equation (5) we get;

$\frac{1.092727\l^3-l^3}{l^3} \times 100$

$0.092727\times 100$

$9.2727\%$

Hence, the volume increases by 9.2727%.

#SPJ3

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