Question

The length of an elastic string is X m when the tension is 8 N, and Y m when the tension is 10 N. The length
in metres when the tension is 18 N is
(1) 44- 5Y
(2) 5Y-4X
(3) 9X– 44
(4) 4Y - 9X​

Answer 1

Answer:

By F=kx

8=kx

so k=8/x

10=ky

k=10 /y

then 4/x=5/y

then 5x=4y

18=(8/x)×L

9x/4=L

Explanation:

now 1 answer=44x-(25/4)x not equals 9x/4

now 2 answer=(25x/4)-4x=(9x/4)

Now we found the answer It is 2