Question

the length of base edge of a square pyramid is 12cm and slant height is 10cm. what isthe hieght of the pyramid?​

Answer 1

Answer:

$\huge {\mathbb{\pink{Hello!!}}}$

Step-by-step explanation:

ANSWER

For a square pyramid

Base edge =s=12cm

Slant height =l=10cm

Since the base of the pyramid is square,

Therefore, a=

2

diagonal

Diagonal of square of base 12

2

cm

a=6

2

cm

h=

10

2

−a

2

=

10

2

−6

2

2

=

100−72

=

18

=3

2

cm

Volume=

3

1

s

2

h=

3

1

×18×8=144

2

cm!

I hope its help uu✔

Thanks ❤

Answer 2

Answer:

Side of square base=12cm

By Pythagoras theorem,

Diagonal²=2(Side²)

=>Diagonal=12√2cm

Half of diagonal=6√2cm

Slant height=10cm

By Pythagoras theorem,

Slant height²=Height²+Half of Diagonal²

H²=(10)²–(6√2)²

=100–72

H=2√7cm