The length of base of a triangle is 2cm more than its altitude. The area of triangle is 24cm². Find the altitude and base of the triangle.
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Answer:
Altitude = 8 cm
Base = 6 cm
Step-by-step explanation:
Let the altitude of Δ = x cm
Base = ( x + 2 ) cm
∵ Area of Δ = 1/2 × Base × Altitude
⇒ 24 cm² = 1/2 (x) (x + 2)
⇒ x² + 2x -24 = 0
⇒ x + (6 - 4)x - 48 = 0
⇒ x + 8x - 6x - 48 = 0
⇒ x ( x + 8 ) - 6 ( x + 8) = 0
⇒ (x - 6) (x + 8) = 0
x = 6 , -8
∵ Length cannot be negative.
∴ Base = x = 6 cm
∴ Altitude= x + 2 = 6 + 2 = 8cm
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