Question

the length of diagonal of a rhombus whose area 216 sq.cm is 24 cm. then find the length of second diagnal

Answer 1

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Area = 216 sq.cm

length of a diagonal is 24cm

Area of rhombus = $\bf\huge\frac{1}{2}$ × $\bf\huge d_{1}$ × $\bf\huge d_{2}$

Hence :-

216 =  $\bf\huge\frac{1}{2}$ × 24 × $\bf\huge d_{2}$

216 = 12 × $\bf\huge d_{2}$

$\bf\huge d_{2}$ = 18cm

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Answer 2

given area = 216 sq.cm.
length of diagonal is 24cm
area of rhombus =1/2×d1×d2
then, 216=1/2×24×d2
216=12×d2
d2= 18cm
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