Question

The length of diagonal of the square
ABCD is 7
$7 \sqrt{2}$
compute one side of
of the
square​

Answer 1

Step-by-step explanation:

Let ABCD is a square in which AB=BC=CD=DA= x units. and AC=BD= 7√2 units.

In right angled triangle ABC , AB^2+BC^2 = AC^2.

or, x^2 + x^2 = (7√2)^2.

or, 2.x^2 = 98.

or, x^2 = 98/2=49.

or, x = √49 = 7 units.

Thus , side of the square = x = 7 units.

Area of the square = (x)^2 = (7)^2 = 49 units ^2.