the length of each side of an equilateral triangle is 24 cm. find the area of its circumscribed circle
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each side of eq triangle=24cm
radius of circumscribed circle=2/3 height of eq triangle
h of eq triangle=root3a=root3*24=24root3
r = 2/3*h=2/3*24root3=16root3
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ar of circle = pi r square=22/7*16root3*16root3=2413.71cmsquare
radius of circumscribed circle=2/3 height of eq triangle
h of eq triangle=root3a=root3*24=24root3
r = 2/3*h=2/3*24root3=16root3
==========
ar of circle = pi r square=22/7*16root3*16root3=2413.71cmsquare
sonasanthosh04:
i think its crct,if its not,i am really sry
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