the length of each side of the rhombus whose diagonals are of length 16cm adn 30cm is
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We know that the diagonals of rhombus bisects each other at 90°
So, by Pythagoras Theorem,
⏩( half of I diagonal )² + ( half of II diagonal )² = side²
⏩ ( 16 / 2 )² + ( 30 / 2 )² = side²
⏩ ( 8 )² + ( 15 )² = side²
⏩ 64 + 225 = side²
⏩ 289 =side²
➡ 17 = side
Hence, side the rhombus is 17 cm
So, by Pythagoras Theorem,
⏩( half of I diagonal )² + ( half of II diagonal )² = side²
⏩ ( 16 / 2 )² + ( 30 / 2 )² = side²
⏩ ( 8 )² + ( 15 )² = side²
⏩ 64 + 225 = side²
⏩ 289 =side²
➡ 17 = side
Hence, side the rhombus is 17 cm
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