Physics, asked by 123shweta, 9 months ago

The length of hour of a wrist watch is 1.5cm Find the magnitude of angular velocity and linear velocity ? ​

Answers

Answered by BrainlyWriter
7

 \bold {\huge {Your ~answer :-}}

W = 1.454 × 10¯⁴ rad/s

V = 2.18 × 10^¯6 m/s

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EXPLAINATION ➣

Length of hour hand of a wrist watch is 1.5cm.

we know, \green{\texttt{angular velocity}}ω = 2π/t

here t is time taken to complete a circle.

\green{\texttt{angular velocity of wrist watch is}}

 =  > w =  \frac{2\pi}{12 \times 60 \times 60}  rad. {sec}^{ - 1} \\  =  > w =  \frac{\pi}{12 \times 1800}

=> w = 1.454 × 10¯⁴

We also know that v = ωr

where v is the linear velocity, ω is the angular velocity and r is the radius of the hour hand.

Putting

 =  > v =  \frac{\pi}{12 \times 1800}  \times 1.5 \\  \\ on \: soving \\  =  > v = 2.18 \times  {10 }^{ - 6} m. {sec}^{ - 1}

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