Question

the length of object measured by vernier caliper is 4.79 cm. If the LC of vernier caliper is 0.01 cm. Calculate the percentage error​

Answer 1

Answer:

L.C. = 0.01 cm

Error = + 0.02 cm ⇒ Positive zero

error = + 0.02 cm

main scale reading (MSR) = 3.60 cm 8

th

vernier scale coincides with main scale

⇒ vernier coincidence (VC) = 8

We know that

Correct diameter = [main scale reading+ (L.C × V.C)] - (error)

= [3.60 + (0.01 × 8)] - [+ 0.002]

= (3.60 + 0.08)- (+0.02)

= 3.68 - 0.02

= 3.66 cm

∴correctradius=

2

diameter

=

2

3.66

=1.83cm