Question

the length of one diagonal of a rhombus is less than the second diagonal by 4cm the area of the rhombus is 30sq.cm find the length of the diagonals

Answer 1

HELLO DEAR,


Sol. Let the length of second diagonal of a rhombus be ‘x’ cm.
∴ the length of first diagonal of a rhombus = x – 4
Area of rhombus = ½ ×  Product of length of diagonals
Area of rhombus = ½ (x) (x – 4)
According to given condition,
 ½ (x) (x – 4) = 30
∴ x ( x – 4) = 60
∴ x2 – 4x = 60
∴ x2 – 4x – 60 = 0
∴ x2 – 10x + 6x – 60 = 0
∴ x(x – 10) + 6(x – 10) = 0
∴ (x – 10) (x + 6 ) = 0
∴ x – 10 = 0  or x + 6 = 0
∴ x = 10  or x = - 6
∵ The length of diagonal of the rhombus cannot be negative.
∴ x = 10
∴ x – 4 = 10 – 4 = 6
∴ The length of first diagonal of a rhombus is 6 cm and second  diagonal is 10 cm.


I HOPE ITS HELP YOU DEAR,

THANKS