Question

The length of parallel chords which are on opposite sides of the centre of a circle are 6 cm and 8 cm. lf radius of the circle is 5 cm, then the distance between these chords is --------​

Answer 1

Answer:

PQ = 8 cm,

MN = 6 cm

∴ AQ = 4 cm,

BN = 3 cm  

∴ OQ2 = OA2 + AQ2  

∴ 52 = OA2 + 42  

∴ OA2 = 25 – 16 = 9  

∴ OA = 3 cm  Also,

ON2 = OB2 + BN2  

∴ 52 = OB2 + 32  

∴ OB = 4 cm  

Now, AB = OA + OB

= 3 + 4

= 7