The length of parallel chords which are on opposite sides of the centre of a circle are 6 cm and 8 cm. lf radius of the circle is 5 cm, then the distance between these chords is --------
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Answer:
PQ = 8 cm,
MN = 6 cm
∴ AQ = 4 cm,
BN = 3 cm
∴ OQ2 = OA2 + AQ2
∴ 52 = OA2 + 42
∴ OA2 = 25 – 16 = 9
∴ OA = 3 cm Also,
ON2 = OB2 + BN2
∴ 52 = OB2 + 32
∴ OB = 4 cm
Now, AB = OA + OB
= 3 + 4
= 7
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