the length of parallel sides of trapezium are in the ratio 7:5 and the distance between them is 14cm of the area of trapezium is 252cmsquare . Find length of its parallel sides.
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2
Hi friend, Harish here.
Here is your answer:
The ratio of parallel sides are - 7 : 5.
So, Let the lengths be 7x & 5x.
We know that,
![Ar\ of\ trapezium= \frac{1}{2}\times height (Sum\ of\ parallel \ sides) Ar\ of\ trapezium= \frac{1}{2}\times height (Sum\ of\ parallel \ sides)](https://tex.z-dn.net/?f=Ar%5C+of%5C+trapezium%3D+%5Cfrac%7B1%7D%7B2%7D%5Ctimes+height+%28Sum%5C+of%5C+parallel+%5C+sides%29+)
⇒![252= \frac{1}{2} \times 14 \times (7x + 5x) 252= \frac{1}{2} \times 14 \times (7x + 5x)](https://tex.z-dn.net/?f=+252%3D+%5Cfrac%7B1%7D%7B2%7D+%5Ctimes+14+%5Ctimes+%287x+%2B+5x%29+)
⇒![252 = 7 (12x) = 84x 252 = 7 (12x) = 84x](https://tex.z-dn.net/?f=252+%3D++7+%2812x%29+%3D+84x+)
⇒![x = \frac{252}{84} = 3 x = \frac{252}{84} = 3](https://tex.z-dn.net/?f=x+%3D++%5Cfrac%7B252%7D%7B84%7D+%3D+3+)
The parallel sides are: 7x = 7 × 3 = 21 cm
5x = 5 × 3 = 15 cm
_____________________________________________________
Hope my answer is helpful to you.
Here is your answer:
The ratio of parallel sides are - 7 : 5.
So, Let the lengths be 7x & 5x.
We know that,
⇒
⇒
⇒
The parallel sides are: 7x = 7 × 3 = 21 cm
5x = 5 × 3 = 15 cm
_____________________________________________________
Hope my answer is helpful to you.
Answered by
1
H\2 ×[ a+b]
7 × 12x = 256
12x=256\7
7 × 12x = 256
12x=256\7
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