Question

The length of pendulum, when g=9.8 ms^(-2) is

Answer 1

question is incomplete as length kf pendulum also depend hain time

Answer 2

Answer:

For seconds' pendulum T = 2.0 s,

g = 9.8 m/s².

From the relation T =

$2\pi \sqrt{ \dfrac{l}{g}}$

$length \: of \: pendulum, \: \: l \: = \frac{g {T}^{2} }{4 {\pi}^{2} }$

$l \: = \frac{9.8 \times (2.0) {}^{2} }{4 \times (3.14) {}^{2} }$

$= 0.994m$

Therefore , the length of seconds' pendulum at a place where g= 9.8m/s² is 0.994 m

Explanation:

The pendulum of a clock which we used to know time in our house, is a seconds' pendulum. It takes time one second in moving from one extreme to the other extreme, so its time period is 2 seconds.