Question

The length of perimeter incrrase in 20 % & wide in 10 % decrease then what % will be change area​

Answer 1

Answer:

Let L = 10

Let W = 10 (a square is a rectangle)

Original area = (LW) = 10*10 = 100

L increases by 20 percent:

(1.2)(10) = 12

W decreases by 20 percent:

(0.8)(10) = 8

New area: (12)*(8) = 96

Percent change:New−OldOld∗100New−OldOld∗100

96−100100=96−100100=

(−.04)∗100(−.04)∗100 = 4 percent decrease

Answer 2

8% gain will be the answer!!!