Question

The length of rectangle exceed it's width by 4m . If it's perimeter is 40 m,find its dimensions

Answer 1

Answer:

Width = 8m

Length = 12m

Step-by-step explanation:

Let the width be x.

Then the length = 4+x

Perimeter of rectangle = 2 (l+b)

40 = 2 ( x + 4+ x)

40 = 2 ( 2x + 4)

40 = 4x + 8

4x = 40 - 8

x = 32/4 = 8

So,width = 8m

And length = 4+8 = 12m

Answer 2

Answer:

☆ Solution ☆

Given :-

• The length of rectangle exceed it's width by 4m
• Perimeter is 40 m.

To Find :-

• Its dimensions .

Step-by-Step-Explaination :-

Let the breadth be x.

Let the length be x + 4

The perimeter of rectangle = 40 m

As we know that :-

Perimeter of rectangle = 2 ( l + b )

According to the question,

40 = 2 ( x + x + 4 )

40 = 2 ( 2x + 4 )

40 = 4x + 4

40 - 8 = 4x

=> 4x = 32

=> x = $\dfrac{32}{4}$

=> x = 8

Hence,

• Width = 8 m
• Length = 8 + 4 = 12 m