the length of rectangle exceeds its width by 5 m.if the width is increased by à m and the length is decreased by 2 m, the area of the new rectangle is 4sq. less than the area of the original rectangle.find the dimensions of the original rectangle?
gurugovi:
solve this fast
please
Answers
Answered by
0
let length be x and breadth be y , Area of rectangle be z
From first condition,
x=y+5
Area of rectangle = length× breadth
x × y = z
y+5 ×(y)=z
y^2 + 5y = z
y^2 + 5y is the area of rectangle
From second condition,
(x-2) × (y+1) = z - 4
(x-2) × (y+1) = (y^2 + 5y)-4
x (y+1) -2 (y+1) = 4y^2 -20y
xy + x - 2y -2 = 4y^2 -20y
4y^2 -20y +2y = xy +x -2
4y^2 -18y -xy -x -2 =0
From first condition,
x=y+5
Area of rectangle = length× breadth
x × y = z
y+5 ×(y)=z
y^2 + 5y = z
y^2 + 5y is the area of rectangle
From second condition,
(x-2) × (y+1) = z - 4
(x-2) × (y+1) = (y^2 + 5y)-4
x (y+1) -2 (y+1) = 4y^2 -20y
xy + x - 2y -2 = 4y^2 -20y
4y^2 -20y +2y = xy +x -2
4y^2 -18y -xy -x -2 =0
Similar questions