Question

the length of rectangle is 10m more than its breadth.if the perimeter of rectnagle 100m. find its length and breadth

Answer 1

• Length of rectangle is 30 m.
• Breadth of rectangle is 20 m.

Step-by-step explanation:

Given:-

• Perimeter of rectangle is 100 m.

To find:-

• Length of rectangle.
• Breadth of rectangle.

Solution:-

Let, Breadth of rectangle be x m.

And, Length of rectangle be x + 10 m.[We take length be x + 10 m because it is given that length is 10 m more than Breadth.]

We know,

Perimeter of rectangle = 2(Length + Breadth)

Put the values:

$\longrightarrow$ 100 = 2×(x + 10 + x)

$\longrightarrow$ 100 = 2x + 20 + 2x

$\longrightarrow$ 100 = 4x + 20

$\longrightarrow$ 100 - 20 = 4x

$\longrightarrow$ 80 = 4x

$\longrightarrow$ x = 80/4

$\longrightarrow$ x = 20

Verification:-

$\longrightarrow$ 100 = 2×(x + 10 + x)

• Put x = 20

$\longrightarrow$ 100 = 2×(20 + 10 + 20)

$\longrightarrow$ 100 = 2×(30 + 10)

$\longrightarrow$ 100 = 60 + 10

$\longrightarrow$ 100 = 100

$\boxed{\sf Hence \: Verified.}$

We have taken,

Breadth be x. So, Breadth of rectangle is 20 m.

Length be x + 10 = 20 + 10 = 30. Thus, Length of rectangle is 30 m.

Answer 2

Answer:

Given :-

• Length is 10 m more than its breadth
• Perimeter = 100 m

To Find :-

Length and breadth

Solution :-

Let the breadth be x

Therefore, Length = x + 10

As we know that

Perimeter of rectangle = 2(l + b)

$\sf \: 100 = 2(x + 10 + x)$

$\sf \: 100 = 2x + 20 + 2x$

$\sf \: 100 = 4x + 20$

$\sf \: 4x = 100 - 20$

$\sf \: 4x = 80$

$\sf \: x = \dfrac{80}{4}$

$\sf \: x = 20$

Hence :-

Breadth = 20 m

Length = x + 10 = 30 m