The length of rectangle is 14 cm more than its breadth. If the perimeter is 448 cm, find the dimensions of the rectangle.
Answers
Explanation:
Let it's breadth be x.
Then it's length=(x+14)
According to the question,
2*{x+(x+14)}=448
=> 2*{2x+14}=448
=> 4x+28=448
=> 4x=448-28
=> 4x=420
=> x=420/4
=> x=105
So , it's length=(x+14) m =(105+14) m = 119 m
Hence,it's breadth is 105 m & it's length is 119 m.
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Given:
The length of the rectangle is 14cm more than its breadth.
The perimeter of the rectangle is 448cm
To be found:
the dimensions(length and breadth value) of the rectangle.
So,
Let the breadth of the rectangle be 'b' cm
So, The length of the rectangle will be = (b+4) cm (ATQ)
Now.
- The formula to find the perimeter of a rectangle is
= 2(length + breadth) units
⇒ 2( (b+14) + b) = 448
⇒ 2b + 14 = 448 ÷ 2
[Taking 2 to RHS]
⇒ 2b + 14 = 224
⇒ 2b = 224 - 14
[Taking 14 to RHS]
⇒ 2b = 210
⇒ b = 210 ÷ 2
[Taking 2 to RHS]
⇒ b = 105
∴ The breadth of the rectangle is 105 cm
And the length of the rectangle is 105 + 14 = 119 cm