Question

the length of rectangle is 3 upon 1 by 7 and the breadth is 4 upon one by two find its perimeter and area

Answer 1

Heya ! 


Here's your Answer ! ↓


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Length = 3 1/7 = (3*7)+1/7 = 21+1/7 = 22/7

Breadth = 4 1/2 = (4*2)+1/2 = 8+1/2 = 9/2 



Perimeter of Rectangle = 2 (Length + Breadth)
 
                                      =  2 ( 22/7 + 9/2 )

                                      = LCM of denominators i.e. 7 and 2 = 14 

                                      =  2 (22*2/7*2 + 9*7/2*7)

                                      =  2 ( 44/14 + 63/14 )

                                      =  2 * 107/14

                                      =  2/1 * 107/14

                                      =  214/14 = 107/7 = 15 2/7 ( Into simplest form )


∴ Perimeter of rectangle = 15 2/7 


⭐ Steps ↓


⇒ First take the LCM of the denominators 

⇒ Then make the proper fraction and then add 

⇒ Then multiply the sum by 2 

⇒ Simplify 


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Area of the rectangle = Length * breadth 

                                  = 22/7 * 9/2 

                                  = 198/14 = 99/7 = 14 1/7 

∴ Area of the rectangle = 14 1/7 


⭐ Steps ↓

⇒ First make it proper Fraction 

⇒ Then multiply 

⇒ Simplify 




Hope this helps you ☺️☺️

Answer 2

Hii Friend ! Here is Your Answer,

$given \\ 3 \frac{1}{7} = length \\ 4 \ \frac{1}{2} = breadth$
$peimeter = 2(l + b) \\ area = l \times b$
Now just convert the given values from mixed fraction to improper fraction.

3 1/7 = 22/7 (Length)

4 1/2 = 9/2 (breadth)

To Find

1. Area of the rectangle.

2. Perimeter of the rectangle.

SOLUTION ÷

1. AREA OF RECTANGLE = L× B

= 22/7 × 9/2 = 99/7 = 14 1/7 (ANS)

2.PERIMETER OF RECTANGLE= 2(L+B)

= 2 ( 9/2 + 22/7) = 2 [ ( 63+44) /14]

= 2( 107/14 )

= 2 × 107/14 = 107 /7 = 15 2/7 (ANS)


SO, The area is 14 1/7 m. sq. and perimetre is 15 2/7 m.

☆☆☆HOPE THIS HELPS YOU A LOT ☺☆☆