Question

the length of rectangle is twice its breadth and its perimeter are 96 metre the length of the rectangle is ​

Answer 1

Step-by-step explanation:

Let the breadth be x ,

2(l+b) = 96

2(2x+x)=96

2×3x=96

6x=96

x=96/6

x=16

therefore breadth means x= 16

length= 2x=2×16=32

Answer 2

Solution :

Given -

• Length of rectangle is twice its breadth

• Perimeter is 96m.

To find -

• Length of the rectangle

Calculation -

Let the breadth of the rectangle be $\tt { x \: m}$

Therefore, length becomes $\tt { 2x \: m}$

We know that,

$\boxed { \large \tt \purple { Perimeter \ of \ rect. = 2 \times ( l + b)}}$

According to formula substitute the value to find length of the rectangle -

$\large \tt { Perimeter \ of \ rect. = 2 \times ( l +b)}$

$\tt { \leadsto 96m = 2 \times ( 2x + x)}$

$\tt { \leadsto 96m = 2 \times 3x}$

$\tt { \leadsto 3x = \dfrac{96}{2} }$

$\tt { \leadsto 3x = 48 }$

$\tt\red { \leadsto x = \cancel {\dfrac {48}{3}} = 16m }$

Therefore,

• $\tt { Breadth = x = 16m}$

• $\tt\purple { Length = 2x = 2 \times 16 = 32m }$

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More-

• Perimeter of rectangle = $\tt { 2 \times (l+b)}$

• Area of rectangle = $\tt { l \times b}$

• Perimeter of square = $\tt { 4 \times sides}$

• Area of square = $\tt { Side \times Side}$

• Perimeter of triangle = sum of all sides

• Area of triangle = $\tt { \dfrac{1}{2} \times b \times h}$

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