Question

The length of rectangle park exceeds its breadth by 17 meters. If the perimeterof the park is 178 meters finnd dimensions of park

Answer 1

let breath= x meter
length = x+17 meter

a/q
=2 (l +b)=178 meter
=2×(x+x+17)=178
=2×2x+34=178
=4x+68=178
=4x=178_68=110
=x= 110÷4=27.50 meter
thus,
breath= 27.50 meter
length = 27.50+17=44.50meter

Answer 2

Answer:

Let the breadth of the park be = x metres

Then the length of the park be = x±17 metres

perimeter of the park=2( length ±breadth)

=2(x±17±x) metres

=2(2x±17) metres

But it is given that the perimeter of the rectangle is 178 metres.

2(2x ±17) =178

4x±34=178

4x =178-34

4x=144

x=144/4=36

Therefore breadth of the park=36 metres

Length of the park=36±17=53 metres.

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