Question

the length of rectangle twice the side of square and it's widht is 6cm greater than the side of square if the area of rectangle is three times the area of square find the dimension of each

Answer 1

side of sq is x
length of rect.. is 2x
width=x+6
acc to question.
2x*(x+6)=3xsquare solve this you find x
put it on length and width amd side of sq... to find their dimensin

Answer 2

Let the side of a square=x cm
=>length of the rectangle =2x cm
Width of the rectangle =(x+6)cm

Area of square=side^2
Area =x^2 Sq cm

Area of rectangle =length × breadth
Area=(2x)(x+6)
Area=2x^2+12x

Area of rectangle=3×(Area of square)
2x^2+12x=3x^2
x^2-12x=0
x (x-12)=0
x=0 (or) x-12=0 =>x=12

If x=0 it can't form a square. So, x=12

•°• Side of the square =12cm
Length of the rectangle = 24cm
Width of the rectangle = 12cm
Area of the square = 144 Sqcm
Area of rectangle = 288 Sqcm

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