The length of resistance wire is increased by 30% by stretching it what is the corresponding change in resistance of the wire
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Answered by
3
Explanation:
let initial length be L
When length was L
R=RHO X L/A
NOW NEW LENGTH =L+ 3/10 L
=13L/10
=1.3L
now new resistance=Rho X 1.3L/A
so the new resistance is 1.3 times the old....
you can write it as 130/100 and apply the formula
((R NEW-R OLD)/R OLD) X 100
which will give you
(130R/100-R)/R X 100
=30R/100 X 100
= 30%
So the new resistance is 30 % higher than old
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