Question

The length of resistance wire is increased by 30% by stretching it what is the corresponding change in resistance of the wire

Answer 1

Explanation:

let initial length be L

When length was L

R=RHO X L/A

NOW NEW LENGTH =L+ 3/10 L

=13L/10

=1.3L

now new resistance=Rho X 1.3L/A

so the new resistance is 1.3 times the old....

you can write it as 130/100 and apply the formula

((R NEW-R OLD)/R OLD) X 100

which will give you

(130R/100-R)/R X 100

=30R/100 X 100

= 30%

So the new resistance is 30 % higher than old

HOPE THIS HELPS

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Answer 2

Explanation:

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