the length of tangent to a circle from a point 17 cm from it Centre is 8 cm then find the radius of the circle .
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by Pythagoras theorem,
OT^2 + PT^2 = OP^2
OT^2 = OP^2 - PT^2
OT^2 = 17^2 - 8^2
OT^2 = 289 -64
OT^2 = 225
OT = √255
OT = 15
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Answer:
15 cm
According to the Pythagoras theorm
AB^2=AC^2+BC^2
(17)^2=AC^2+8^2
AC^2=17^2 - 8^2
AC^2 = 289 - 64
AC^2 = 225
AC = 15 CM
therfore required radius of the circle is 15 cm
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