Question

The length of the aluminium rod at temperature 303 K is 50m what would be its increase in length when it is heated to 323K(the linear coefficient of aluminium is 23×10^-6 K^-1

Answer 1

Increase in length is  $2.3\times 10^{-2}\ m.$

Given :

Length of aluminium rod , L = 50 m.

Initial temperature , $T_i=303 \ K.$

Final temperature , $T_f=323\ K.$

Linear coefficient of aluminium , $\alpha=23\times 10^{-6}\ K^{-1}.$

We know ,

Change in length , $\Delta L=L\times \alpha\times(T_f-T_i)$

Putting all the values in above equation.

We get , $\Delta L=2.3\times 10^{-2}\ m.$

Therefore, increase in length is  $2.3\times 10^{-2}\ m.$

Hence, this is the required solution.

Learn More :

Expansion

https://brainly.in/question/7335689